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Foundational

The Rope Around the Earth

A classic brainteaser about how much a rope wrapped snugly around the Earth's equator needs to be lengthened to lift it one meter off the ground everywhere — and why the answer is surprisingly small.

Imagine a rope wrapped snugly around the Earth's equator, then imagine adding just one extra meter of rope and pulling it into a perfect circle, lifted evenly off the ground all the way around. How big is the gap between the ground and the rope? Most people guess it must be microscopically small, since one meter is nothing next to the Earth's roughly 40,000-kilometer circumference. The actual gap is about 16 centimeters — big enough to slide a large book underneath, everywhere around the entire planet.

The trick is that the answer doesn't depend on the circle's size at all. Circumference is C=2πrC = 2\pi r, so adding a fixed length ΔC\Delta C to the rope changes the radius by Δr=ΔC/(2π)\Delta r = \Delta C / (2\pi) — a formula with no rr in it. Whether the "planet" is a basketball or the Earth, adding one extra meter of rope always lifts it by the same 1/(2π)0.1591/(2\pi) \approx 0.159 meters, about 16 cm.

Because circumference scales linearly with radius (C=2πrC = 2\pi r), the radius gained per unit of extra rope is constant and independent of the circle's original size — the puzzle's "surprising" answer is really just that Δr=ΔC/(2π)\Delta r = \Delta C/(2\pi) has no rr term to shrink it for a huge planet.

Worked example. Adding exactly 1 meter of rope: Δr=1/(2π)0.159\Delta r = 1 / (2\pi) \approx 0.159 meters, or about 15.9 cm, regardless of whether the sphere is the Earth or a soccer ball. Adding 2 meters instead simply doubles the gap to roughly 31.8 cm — the relationship is exactly linear in the extra length, never in the planet's size.

Related concepts

Practice in interviews

Further reading

  • Classic mathematical recreations, circle-circumference puzzles
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