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Finite Population Correction and Sampling Fractions

When you sample a large chunk of a small, finite population, the usual standard-error formula overstates your uncertainty — the finite population correction shrinks it back down.

Standard-error formulas assume you're drawing a tiny sample from an effectively infinite population — each draw barely changes what's left to draw from. That assumption breaks when you sample, say, 400 accounts out of a firm with only 1,000 total. Once you've looked at 40% of everyone, there's a lot less left to be surprised by, and treating the sample as if it came from an infinite pool overstates how uncertain your estimate really is.

The finite population correction (FPC) fixes this by multiplying the standard error by NnN1\sqrt{\frac{N-n}{N-1}}, where NN is the population size and nn is the sample size. As nn grows relative to NN, this factor shrinks toward zero, squeezing the standard error down — right up to n=Nn = N, a full census, where uncertainty about the mean is exactly zero, since you've counted everyone.

The correction factor depends only on the sampling fraction n/Nn/N, not on the sizes themselves — sampling 10 out of 100 gets the same shrinkage as sampling 10,000 out of 100,000. When n/Nn/N is small (under about 5%), the correction is negligible and ordinary formulas are fine.

Worked example. A pension fund wants the average balance across its N=2,000N = 2{,}000 accounts and samples n=500n = 500 of them, finding a sample standard error (uncorrected) of $120. The FPC factor is (2000500)/(20001)=1500/19990.866\sqrt{(2000-500)/(2000-1)} = \sqrt{1500/1999} \approx 0.866. Corrected standard error: 120 \times 0.866 \approx \104$ — about 13% tighter than the naive formula would claim, simply because 25% of the whole population was already in hand.

Related concepts

Practice in interviews

Further reading

  • Cochran, Sampling Techniques (ch. 2)
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